A copper wire has a square cross-section, $2.0\, mm$ on a side. It carries a current of $8\, A$ and the density of free electrons is $8 \times {10^{28}}\,{m^{ - 3}}$. The drift speed of electrons is equal to
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(a) ${v_d} = \frac{i}{{nAe}} = $$\frac{8}{{8 \times {{10}^{28}} \times {{(2 \times {{10}^{ - 3}})}^2} \times 1.6 \times {{10}^{ - 19}}}}$
$=$ $0.156 \times {10^{ - 3}}\, m/sec$.
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