The potential difference between point $A$ and $B$ is ............. $V$
A$\frac{{20}}{7}$
B$\frac{{40}}{7}$
C$\frac{{10}}{7}$
D$0$
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D$0$
d (d) The given circuit is a balanced wheatstone bridge circuit. Hence potential difference between $A$ and $B$ is zero.
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$(i)$ In case of potentiometer, no current flows through the cell.
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$(iv)$ The sensitivity of the galvanometer, when using a potentiometer is not relevant.
Which of these reasons are correct?
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