A copper wire of length $4.0m$ and area of cross-section $1.2\,c{m^2}$ is stretched with a force of $4.8 \times {10^3}$ $N.$ If Young’s modulus for copper is $1.2 \times {10^{11}}\,N/{m^2},$ the increase in the length of the wire will be
  • A$1.33 \,mm$
  • B$1.33 \,cm$
  • C$2.66\, mm$
  • D$2.66\, cm$
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