A copper wire $(Y = 1 \times 10^{11}\, N/m^2)$ of length $6\, m$ and a steel wire $(Y = 2 \times 10^{11}\, N/m^2)$ of length $4\, m$ each of cross section $10^{-5}\, m^2$ are fastened end to end and stretched by a tension of $100\, N$. The elongation produced in the copper wire is ......... $mm$
Medium
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$\Delta \mathrm{L}=\frac{\mathrm{FL}}{\mathrm{YA}}$
$\Delta \mathrm{L}=\frac{(100)(6)}{10^{11}\left(10^{-5}\right)}=0.6 \times 10^{-3} \mathrm{m}$
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