The adjacent graph shows the extension $(\Delta l)$ of a wire of length $1m$ suspended from the top of a roof at one end with a load $W$ connected to the other end. If the cross sectional area of the wire is ${10^{ - 6}}{m^2},$ calculate the young’s modulus of the material of the wire
IIT 2003, Medium
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(a)From the graph $l = {10^{ - 4}}m,\;F = 20N$
$A = {10^{ - 6}}{m^2},\;L = 1m$
$Y = \frac{{FL}}{{Al}}$$ = \frac{{20 \times 1}}{{{{10}^{ - 6}} \times {{10}^{ - 4}}}} = 20 \times {10^{10}} = 2 \times {10^{11}}N/{m^2}$
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