MCQ
A cricket ball is thrown by a player at a speed of $20\,m / s$ in a direction $30^{\circ}$ above the horizontal. The maximum height attained by the ball during its motion is $........\,m$ $\left( g =10\,m / s ^2\right)$
  • $5$
  • B
    $10$
  • C
    $20$
  • D
    $25$

Answer

Correct option: A.
$5$
a
$H =\frac{ u ^2 \sin ^2 \theta}{2 g }=\frac{(20)^2 \sin ^2 30^{\circ}}{2(10)}$

$=5$

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