Let,
$V _1, V_2, V_3 \rightarrow$ Volume of the three cubes
$a_1, a_2, a_3 \rightarrow$ Side of the three cubes
We know that,
$a^3=V$
So,
$a _1^3 = V$
$a _1^3 =\frac{1}{8}$
$a _1 =\frac{1}{2} \ cm$
Similarly,
$a _2^3 =1$
$a _2 =1\ cm$
And;
$a _3^3 =8$
$a _2 =2\ cm$
So the height of the resulting structure,
$=\frac{1}{2}+1+2$
$=0.5+1+2$
$=3.5\ cm$
The height of the structure is $3.5\ cm$ .
Hence, the correct choice is $(a)$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
