Let,
$\mathrm{V}_1, \mathrm{~V}_2, \mathrm{~V}_3 \rightarrow$ Volume of the three cubes
$a_1, a_2, a_3 \rightarrow$ Side of the three cubes
We know that,
$a^3=V$
So,
$\text{a}^3_1=\text{V}$
$\text{a}^3_1=\frac18$
$\text{a}_1=\frac12\text{cm}$
Similarly,
$\text{a}^3_2=1$
$\text{a}_2=1\text{cm}$
And;
$\text{a}^3_3=8$
$\text{a}_2=2\text{cm}$
So the height of the resulting structure,
$=\frac12+1+2$
$= 0.5 +1 + 2$
$= 3.5\ cm$
The height of the structure is $3.5\ cm$.
Hence, the correct choice is $(a)$.
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