Question
A current $I$ flowing through the loop as shown in the adjoining figure. The magnetic field at centre $O$ is
✓
Answer
$\mathrm{B}=\frac{\mu_{0} \mathrm{I}}{4 \pi}\left(\frac{3 \pi}{2 \mathrm{R}}+\frac{\pi}{2 \times 2 \mathrm{R}}\right)=\frac{\mu_{0} \mathrm{I}}{4} \times \frac{(6+1)}{4 \mathrm{R}}=\frac{7 \mu_{0} \mathrm{I}}{16 \mathrm{R}}$
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