A current loop, having two circular arcs joined by two radial lines is shown in the figure. It carries a current of $10\, A$. The magnetic field at point $O$ will be close to
JEE MAIN 2019, Medium
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Magnetic field at clentre of an area subtending angle $\theta$ at the centre $\frac{\mu_{0} I}{4 \pi r} \theta$
$B=\left(\frac{\mu_{0}}{4 \pi}\right) \times 10\left(\frac{1}{3 \times 10^{-2}}-\frac{1}{5 \times 10^{-2}}\right) \frac{\pi}{4}$
$\quad=B=\frac{\pi}{30} \times 10^{-4}=\frac{\pi}{3} \times 10^{-5} \approx 10^{-5}$
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