Question
A current of $1.50A $ was passed through an electrolytic cell containing $AgNO_3$ solution with inert electrodes. The weight of Ag deposited was $1.50g$. How long did the current flow?

Answer

$\text{Ag}^++\text{e}^-\xrightarrow{ \ \ \ \ \ \ }\text{Ag}$
Quantity of charge required to deposit $108g$ of silver $= 96500C$
$\therefore$ Quantity of charge required to deposit $1.50g$ of silver $=\frac{96500}{108}\times1.50=1340.28\text{C}$
$\text{t}=\frac{\text{Q}}{\text{I}}$
$\therefore$ Time taken $=\frac{1340.28}{1.50}=893.52\text{s}$

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