A current of $2\, mA$ was passed through an unknown resistor which dissipated a power of $4.4\, W$. Dissipated power when an ideal power supply of $11\, V$ is connected across it is
JEE MAIN 2019, Medium
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$R =\frac{P}{l^{2}}=\frac{4.4}{4 \times 10^{-6}} \,\Omega $
$ P^{\prime}= \frac{V^{2}}{R}=\frac{11 \times 11 \times 4 \times 10^{-6}}{4.4} \,W $
$=11 \times 10^{-5} \,W $
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