A current of $5\; {A}$ is passing through a non-linear magnesium wire of cross-section $0.04\; {m}^{2}$. At every point the direction of current density is at an angle of $60^{\circ}$ with the unit vector of area of cross-section. The magnitude of electric field at every point of the conductor is ....${V} / {m}$ (Resistivity of magnesium is $\rho=44 \times 10^{-8}\, \Omega m$)
  • A$11 \times 10^{-3}$
  • B$11 \times 10^{-5}$
  • C$11 \times 10^{-7}$
  • D$11 \times 10^{-2}$
JEE MAIN 2021, Diffcult
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