MCQ
A current source sends a current $\text{I}-\text{i}_0\cos(\omega\text{t}).$ when connected across an unknown load, it gives a voltage output of $\text{v}=\text{v}_0\sin[\omega\text{t}+(\frac{\pi}{4})]$across that load. then the voltage across the current source may be brought in phase with the current through it by.
- AConnecting an inductor in series with the load
- BConnecting a capacitor in series with the load
- CConnecting an inductor in parallel with the load
- DConnecting a capacitor in parallel with the load
