MCQ
A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be
- A$0.8 m/s^2$
- B$0.4 m/s^2$
- ✓$1.6\,{\pi ^2}\,m/{s^2}$
- D$0.4\,{\pi ^2}\,m/{s^2}$
✓
Answer
Correct option: C.
$1.6\,{\pi ^2}\,m/{s^2}$
c
(c) Centripetal acceleration $ = 4\pi^2n^2r=4\pi^2×(1)×0.4=1.6\pi^2$
(c) Centripetal acceleration $ = 4\pi^2n^2r=4\pi^2×(1)×0.4=1.6\pi^2$
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