Question
A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown Fig. If he maintains constant speed of $10ms^{–1}$, what is his acceleration at point R in magnitude and direction?

 

Answer

The path of the cyclist at R is circular of constant radius 1km with centre O and he is moving with constant speed 10m/ s. So his motion is uniform circular motion at R.

Hence, the R = 1000m, v =10m/ s

$\therefore\ \text{a}_\text{c}=\frac{\text{v}^2}{\text{R}}=\frac{10\times10}{1000}=\frac{1}{10}=0.1\text{m/ s}^2$ along RO.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free