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Question Bank [ 2022 ] — Physics STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsQuestion Bank [ 2022 ]3 Marks
Question
A cylinder containing one gram molecule of the gas was compressed adiabatically until its temperature rose from 27°C to 97°C. Calculate the work done and heat produced in the gas (? = 1.5).
✓

Answer

Given:
$ n =1, \gamma=1.5$
$T _{ f }- T _{ i }=97-27=70^{\circ} C $
We know, $R=8.31 J / mol K$
To find:
i. Work done (W)
ii. Heat produced (Q)
Formula: $W =\frac{ nR \left( T _{ f }- T _{ i }\right)}{(1-\Upsilon)}$
Calculation:
From formula,
$ W=\frac{1 \times 8.31 \times 70}{1-1.5}$
$=-11.63 \times 10^2 J $
As work done on the gas is converted into heat, the (rising temperature of the gas,
heat produced, $Q =\frac{11.63 \times 10^2}{4.18} cal \approx 2 7 8 cal$
i. Work done is $-11.63 \times 10^2 J$
ii. The heat produced in the gas 278 cal.

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