Hence ${K_{eq}} = \frac{{{K_1}{A_1} + {K_2}{A_2}}}{{{A_1} + {A_2}}}$; where $A_1$ =
Area of cross-section of inner cylinder = $\pi$ $R_2$ and ${A_2} = $Area of cross-section of cylindrical shell $ = \pi \{ {(2R)^2} - {(R)^2}\} = 3\pi {R^2}$
==> ${K_{eq}} = \frac{{{K_1}(\pi {R^2}) + {K_2}(3\pi {R^2})}}{{\pi {R^2} + 3\pi {R^2}}} = \frac{{{K_1} + 3{K_2}}}{4}$