A cylindrical tube $(L = 120\,cm.)$ is resonant with a tuning fork of frequency $330\,Hz$. If it is filling by water then to get resonance minimum length of water column is ..... $cm$ $(V_{air} = 330\,m/s)$
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$\mathrm{f}=\frac{\mathrm{nv}}{4 \mathrm{C}}$
$\mathrm{n}=\frac{\mathrm{f}(4 \mathrm{L})}{\mathrm{v}}$
$n=\frac{330 \times 4}{330} \times \frac{120}{10}$
$\boxed{{\text{n}} = 4.80}$
$n=3$
$3 \times 330=\frac{3 \times 330}{4 L}$
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