
Pressure is same at all the points of base.
i.e. Pressure at $M=$ Pressure at $N$
Also, pressure applied anywhere to the fluid is equally transmitted in all directions.
So, pressure at base $=$ pressure due to oil column of height $h+$ pressure due to water column of height $H$.
$\Rightarrow \rho_o g h+\rho_w g H \Rightarrow g\left(\rho_0 \cdot h+\rho_w H\right)$
Density of whole blood, $\rho=1.06 \times 10^{3} \;kg m ^{-3}$
[Given: Surface tension of the liquid is $0.075 \mathrm{Nm}^{-1}$, atmospheric pressure is $10^5 \mathrm{~N} \mathrm{~m}^{-2}$, acceleration due to gravity $(g)$ is $10 \mathrm{~m} \mathrm{~s}^{-2}$, density of the liquid is $10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and contact angle of capillary surface with the liquid is zero]


