$Therefore,V = {V_1} = {V_2}$
$i.e.,\frac{{\pi {p_1}r_1^4}}{{8\eta {l_1}}} = \frac{{\pi {p_2}r_2^4}}{{8\eta {l_2}}}$
$or\,\,\,\,\,\,\frac{{{p_1}r_1^4}}{{{l_1}}} = \frac{{{p_2}r_2^4}}{{{l_2}}}$
$\,\,\,\,{P_2} = 4\,{P_1}\,\,and\,{l_2} = {l_1}/4$
$\frac{{{p_1}r_1^4}}{{{l_1}}} = \frac{{4{p_1}r_2^4}}{{{l_1}/4}} \Rightarrow r_2^4 = \frac{{r_1^4}}{{16}}$
$ \Rightarrow {r_2} = {r_1}/2$
$(A)$ $\beta=0$ when $a= g / \sqrt{2}$
$(B)$ $\beta>0$ when $a= g / \sqrt{2}$
$(C)$ $\beta=\frac{\sqrt{2}-1}{\sqrt{2}}$ when $a= g / 2$
$(D)$ $\beta=\frac{1}{\sqrt{2}}$ when $a= g / 2$
