Therefore, $( 3)$ and $( 4)$ are wrong. Further,
$\mathrm{B}=\frac{\mu_{0} \mathrm{Nia}^{2}}{2\left(\mathrm{a}^{2}+\mathrm{x}^{2}\right)^{3 / 2}}$
where a is the radius of the coil
At $\mathrm{x}=0, \quad \mathrm{B}=\frac{\mu_{0} \mathrm{Ni}}{2 \mathrm{a}}$
when $\mathrm{x} \rightarrow \infty, \mathrm{B} \rightarrow 0$
Slope of the graph will be $\frac{\mathrm{dB}}{\mathrm{dx}}=\frac{3 \mu_{0} \mathrm{Nia}^{2} \mathrm{x}}{2\left(\mathrm{a}^{2}+\mathrm{x}^{2}\right)^{5 / 2}}$
which means at $\mathrm{x}=0,$ slope is equal to zero or tangent to the graph at $\mathrm{x}=0$ must be parallel to $x$ - axis. Hence $(2)$ is correct and $(1)$ is wrong.
$(A)$ $\vec{B}(x, y)$ is perpendicular to the $x y$-plane at any point in the plane
$(B)$ $|\vec{B}(x, y)|$ depends on $x$ and $y$ only through the radial distance $r=\sqrt{x^2+y^2}$
$(C)$ $|\vec{B}(x, y)|$ is non-zero at all points for $r$
$(D)$ $\vec{B}(x, y)$ points normally outward from the $x y$-plane for all the points between the two loops

| Induced current | Force on left side | Force on right side | |
| $a.$ | Counter clockwise | To the left | To the right |
| $b.$ | clockwise | To the left | To the right |
| $c.$ | Counter clockwise | To the right | To the left |
| $d.$ | clockwise | To the right | To the left |


