A circular coil of $20$ $turns$ and radius $10\, cm$ is placed in uniform magnetic field of $0.10\, T$ normal to the plane of the coil. If the current in coil is $5\, A$, then the torque acting on the coil will be...... $Nm$
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(d) Since $\theta = 0^\circ $ so $\tau = 0$ $(\,\tau = NiAB\sin \theta )$
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