a
Given:
$A=0.01 \mathrm{~m}^2, \mathrm{I}=10 \mathrm{~A}, \mathrm{~B}=0.1 \mathrm{~T},$
$\theta=0^{\circ}$
To find:
Torque acting on the loop, $\tau$
Solution:
Magnetic moment, $M=(I)(A)$
The torque acting on the loop is given as, $\vec{\tau}=\vec{M} \times \vec{B}$
$\tau=M B \sin \theta $
$\tau=1 A B \sin 0$
$\tau=0\;\mathrm{Nm}$