A circular table is rotating with an angular velocity of rad / s … - Vidyadip

Question

A circular table is rotating with an angular velocity of $\omega \mathrm{rad} / \mathrm{s}$ about its axis (see figure). There is a smooth groove along a radial direction on the table. A steel ball is gently placed at a distance of $1 \mathrm{~m}$ on the groove. All the surface are smooth. If the radius of the table is $3 \mathrm{~m}$, the radial velocity of the ball w.r.t. the table at the time ball leaves the table is $x \sqrt{2} \omega \mathrm{m} / \mathrm{s}$, where the value of $x$ is............

✓

Answer

$a_c=\omega^2 x$

$\frac{v d v}{d x}=\omega^2 x$

$\int_0^v v d v=\int_1^3 \omega^2 x d x$

$\frac{v^2}{2}=\omega^2\left[\frac{x^2}{2}\right]$

$\frac{v^2}{2}=\frac{\omega^2}{2}\left[3^2-1^2\right]$

$v=2 \sqrt{2} \omega$

$x=2$

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