
- A$1 : 2$
- ✓$1 :\sqrt 2 $
- C$2 : 1$
- D$\sqrt 2 :1$

$S_{C D}=\frac{1}{2} g \cos 60 t_{C D}^{2}$
But,
$S_{A B}=S_{C D}$
$\therefore \frac{S_{A B}}{S_{C D}}=\frac{\frac{1}{2} g t_{A B}^{2}}{\frac{1}{2} g \cos 60 t^{2} C D}$
$1=2 \frac{t^{2}_{AB}}{t^{2}_{CD}}$
$\frac{t_{A B}}{t_{C D}}=\frac{1}{\sqrt{2}}$
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Statement$-I :$ An elevator can go up or down with uniform speed when its weight is balanced with the tension of its cable.
Statement$-II :$ Force exerted by the floor of an elevator on the foot of a person standing on it is more than his/her weight when the elevator goes down with increasing speed.
In the light of the above statements, choose the correct answer from the options given below :
