Maharashtra BoardEnglish MediumSTD 7MathsFractions3 Marks
Question
A film show lasted for
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Answer
Total duration of the film $=3\frac{2}{3}=\frac{11}{3}$ hours.
Time spent on advertisement $=1\frac{1}{2}=\frac{3}{2}$ hours.
$\therefore$ Actual duration of the film $=\frac{11}{3}-\frac{3}{2}$
$=\frac{13}{6}=2\frac{1}{6}$ hours.
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