A flag pole 18m high casts a shadow 9.6m long. Find the distance of the top of the pole from the far end of the shadow.
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Pole PL = 18m casts shadow LS = 9.6m
The required distance between top of pole and far end of shadow is equal to PS as pole is vertical so $\angle\text{L}=90^\circ.$
$\therefore$ By pythagoras theorem,
$PS^2 = 18^2 + 9.6^2$
$\Rightarrow PS^2 = 324 + 92.16$
$\Rightarrow PS^2 = 416.16$
$\Rightarrow PS = 20.4m$
Hence, the required distance = 20.4m
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