$(I)=\frac{q}{t}=\frac{n e}{t}=\frac{n}{t} \times e$
$=10^{7} \times\left(1.6 \times 10^{-19}\right)=1.6 \times 10^{-12}\; A$


Statement $1 :$ The possibility of an electric bulb fusing is higher at the time of switching $ON.$
Statement $2:$ Resistance of an electric bulb when it is not lit up is much smaller than when it is lit up.

