In the circuit here, the steady state voltage across capacitor $C$ is a fraction of the battery $e.m.f.$ The fraction is decided by
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(b) In steady state potential difference across capacitor
$V_2$$=$potential difference across resistance ${R_2} = \left( {\frac{{{R_2}}}{{{R_1} + {R_2}}}} \right)\,V$
Hence $V_2$ depends upon $R_2$ and $R_1$
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