MCQ
A force $F$ acting on an object varies with distance $x$ as shown in the figure. The work done by the force in moving the object from $x = 0$ and $x = 20m$ is:
- A$500J$
- B$1000D$
- ✓$1500J$
- D$2000D$
✓
Answer
Correct option: C.
$1500J$
Area under force displacement curve is the work done in that interval
Area under the given figure Area of surface Area of triangle. $= +$
Work done $= 10\times 100+\frac{1}{2}\times 10\times 100$
$= 1000 + 500$
$= 1500J$
Area under the given figure Area of surface Area of triangle. $= +$
Work done $= 10\times 100+\frac{1}{2}\times 10\times 100$
$= 1000 + 500$
$= 1500J$
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