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STD 11 - 4.1 , newtons laws of motion — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 4.1 , newtons laws of motion4 Marks
MCQ
A force-time graph for a linear motion is shown in figure where the segments are circular. The linear momentum gained between zero and $8$ second is
  • A
    $ - 2\pi \,newton \times second$
  • ✓
    $Zero\;newton \times second$
  • C
    $ + 4\pi \,newton \times second$
  • D
    $ - 6\pi \,newton \times second$
✓

Answer

Correct option: B.
$Zero\;newton \times second$
b
(b)As the area above the time axis is numerically equal to area below the time axis therefore net momentum gained by body will be zero because momentum is a vector quantity.

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