Question
A function $f :[-5,9] \rightarrow R$ is defined as follow:
$f(x)=\left\{\begin{array}{ll}6 x+1 ; & -5 \leq x<2 \\5 x^2-1 ; & 2 \leq x<6 \\3 x-4 ; & 6 \leq x \leq 9\end{array} \text { Find } f(-3)+f(2)\right.$

Answer

$f(x)=6 x+1 ; x=\{-5,-4,-3,-2,-1,0,1\}$
$f(x)=5 x^2-1 ; x=\{2,3,4,5\}$
$f(x)=3 x-4 ; x=\{6,7,8,9\}$
$f(-3)+f(2)$
$f(x)=6 x+1$
$f(-3)=6(-3)+1=-18+1=-17$
$f(x)=5 x^2-1$
$f(2)=5(2)^2-1=20-1=19$
$f(-3)+f(2)=-17+19=2$

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