Question
A function $f:[-5,9] \rightarrow R$ is defined as follow:
$f(x)=\left\{\begin{array}{ll}6 x+1 ; & -5 \leq x<2 \\5 x^2-1 ; & 2 \leq x<6 \\3 x-4 ; & 6 \leq x \leq 9\end{array} \text { Find } 2 f(4)+f(8)\right.$

Answer

$f(x)=6 x+1 ; x=\{-5,-4,-3,-2,-1,0,1\}$
$f(x)=5 x^2-1 ; x=2,3,4,5$
$f(x)=3 x-4 ; x=\{6,7,8,9\}$
$2 f(4)+f(8)$
$f(x)=5 x^2-1$
$f(4)=5(4)^2-1=5(16)-1$
$=80-1=79$
$f(x)=3 x-4$
$f(8)=3(8)-4=24-4=20$
$2 f(4)+f(8)=2(79)+20$
$=158+20$
$=178$

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