Question
A function $f$ is defined by $f(x)=2 x-3$ find $\frac{f(0)+f(1)}{2}$

Answer

$f(x)=2 x-3 $
$ f(0)=2(0)-3=-3 $
$ f(1)=2(1)-3=2-3=-1 $
$ \frac{f(0)+f(1)}{2}=\frac{-3-1}{2}=\frac{-4}{2}$
$ \frac{f(0)+f(1)}{2}=-2$

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