A _ ( g ) B _ ( g ) + C 2 (g) The correct relationship between K_P, and equilibrium pressure P is

A _ ( g ) B _ ( g ) + C 2 (g) The correct relationship between K_…

MCQ

$ A _{( g )} \rightleftharpoons B _{( g )}+\frac{ C }{2}(g)$ The correct relationship between $K_P, \alpha$ and equilibrium pressure $P$ is

A
$K_P=\frac{\alpha^{1 / 2} P ^{1 / 2}}{(2+\alpha)^{1 / 2}}$
B
$K_P=\frac{\alpha^{3 / 2} P^{1 / 2}}{(2+\alpha)^{1 / 2}(1-\alpha)}$
C
$K_P=\frac{\alpha^{1 / 2} P^{3 / 2}}{(2+\alpha)^{3 / 2}}$
D
$K _{ P }=\frac{\alpha^{1 / 2} P ^{1 / 2}}{(2+\alpha)^{3 / 2}}$

✓

Answer

$A_{(g)} \rightleftharpoons B_{(g)}+\frac{c}{2}(g)$
$t=t_{cq} \quad(1-\alpha) \alpha \frac{\alpha}{2}$
$P_{B}=\frac{\alpha}{\left(1+\frac{\alpha}{2}\right)} \cdot P, P_{A}=\frac{(1-\alpha)}{\left(1+\frac{\alpha}{2}\right)} \cdot P, P_{C}=\frac{\frac{\alpha}{2}}{\left(1+\frac{\alpha}{2}\right)} \cdot P$
$K_{P}=\frac{P_{B} \cdot P_{C}^{\frac{1}{2}}}{P_{A}}$
$=\frac{(\alpha)^{\frac{3}{2}}(P)^{\frac{1}{2}}}{(1-\alpha)(2+\alpha)^{\frac{1}{2}}}$

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