A galvanometer has $30$ divisions and a sensitivity $16\,\mu A/{\rm{div}}{\rm{.}}$ It can be converted into a voltmeter to read $3\, V$ by connecting
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(a) $(R + G)\,{i_g} = V$
$ \Rightarrow $ $(R + G) = \frac{V}{{{i_g}}}$
$ = \frac{3}{{30 \times 16 \times {{10}^{ - 6}}}} = 6.25\,k\Omega $
$\therefore $ Value of $R$ is nearly equal to $6\,k\Omega $
This is connected in series in a voltmeter.
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