A galvanometer of resistance $100 \Omega$ when connected in series with $400 \Omega$ measures a voltage of upto $10 \mathrm{~V}$. The value of resistance required to convert the galvanometer into ammeter to read upto $10 \mathrm{~A}$ is $\mathrm{x} \times 10^{-2} \Omega$. The value of $\mathrm{x}$ is :
  • A$2$
  • B$800$
  • C$20$
  • D$200$
JEE MAIN 2024, Diffcult
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