A helium nucleus makes a full rotation in a circle of radius $0.8$ metre in two seconds. The value of the magnetic field $B$ at the centre of the circle will be
  • A$\frac{{{{10}^{ - 19}}}}{{{\mu _0}}}$
  • B${10^{ - 19}}{\mu _0}$
  • C$2 \times {10^{ - 10}}{\mu _0}$
  • D$\frac{{2 \times {{10}^{ - 10}}}}{{{\mu _0}}}$
Medium
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