MCQ
A gas present in a cylinder, expands against a constant pressure of $1\, atm$ from a volume of $2\, litre$ to a volume of $6\, litre$. In doing so, it absorbs $800\, joule$ heat from surrounding. The change in internal energy of process is.....$ joule$
  • A
    $+305.8$
  • B
    $+796$
  • $+395$
  • D
    $-463.28$

Answer

Correct option: C.
$+395$
c
since,work is done against constant pressure and thus, irreversible.

Given, $\Delta V=(6-2)=4$ litre; $P=1$ atm

$\therefore W=-1 \times 4$ litre-atm $=-4 \times 1.01325 \times 10^{2} J$

$=405.3 J$

Now from first law of thermodynamics

$q =\Delta U - W$

$800=\Delta U+405.3$

$\therefore \Delta U=394.7$ Joule

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