A gas taken through cyclic process $ABCA$ is shown in figure. If $2.4\,cal.$ of heat is given in the process, what is value of $J$ ...... $J/cal$ (mechanical equivalent of heat)?
Medium
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for cyclic process
$\mathrm{dQ}=\mathrm{d} \mathrm{W}$
$\Rightarrow \mathrm{d} \mathrm{Q}=\frac{1}{2} \times 200 \times 100 \times 10^{-6} \times 10^{3} \mathrm{J}=10 \mathrm{Joule}$
also $dQ$ $=2.4 \mathrm{cal}$
$\Rightarrow \mathrm{J}=\frac{10}{2.4}=4.17 \mathrm{J} / \mathrm{cal}$
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