- A$Sb$
- B$p$
- C$As$
- ✓$Bi$
$\left.\begin{array}{l} N \\ p \end{array}\right] \rightarrow$ Non metal
$\left.\begin{array}{l} As \\ Sb \end{array}\right] \rightarrow$ Metalloid
$Bi ] \rightarrow$ Metal
Hydrides of group $15$ elements are $NH _{3}$
$PH _{3}$
$AsH _{3}$
$SbH _{3}$
$BiH _{3}$
In $NH _{3}$, hydrogen atom gets partial positive charge due to less electronegativity.
But in $BiH _{3},$ hydrogen atom gets partial negative charge because hydrogen is more electronegative than bismuth.
i.e. $BiH _{3}$ is a strong reducing agent than others because we know that $H$ is a strong reducing agent.
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|
सूची-$I$ coordination compounds |
सूची-$II$ numbar of unpaired electrons |
| $A$ $\left[ Cr ( CN )_6\right]^{3-}$ | $I$ $0$ |
| $B$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ | $II$ $3$ |
| $C$ $\left[ Co \left( NH _3\right)_6\right]^{3+}$ | $III$ $2$ |
| $D$ $\left[ Ni \left( NH _3\right)_6\right]^{2+}$ | $IV$ $4$ |
Choose the correct answer from the options given below :-