Question
A hanging mass $M$ is connected to a four times bigger mass by using a string-pulley arrangement. as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by $2\,Mg$ force. In this situation. tension in the string is $\frac{x}{5}$ $Mg$ for $x =$ Neglect mass of the string and friction of the block (bigger mass) with ice slab. (Given $g=$ acceleration due to gravity)

Answer

Using $\overrightarrow{ F }_{\text {net }}=\mu \vec{a}$

$2 Mg - T =4 Ma$

$T - Mg = Ma$

_______________

$\Rightarrow a =\frac{ g }{5}$

$T = Mg + Ma = Mg +\frac{ Mg }{5}=\frac{6}{5}\,Mg$

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