A healthy adult of height $1.7 \,m$ has an average blood pressure $( BP )$ of $100 \,mm$ of $Hg$. The heart is typically at a height of $1.3 \,m$ from the foot. Take, the density of blood to be $10^3 \,kg / m ^3$ and note that $100 \,mm$ of $Hg$ is equivalent to $13.3 \,kPa$ (kilo pascals). The ratio of $BP$ in the foot region to that in the head region is close to
KVPY 2019, Diffcult
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(c)
Pressure at head level $=p_{\text {heart }}-\rho g h$
$=13.3-10^3 \times 10 \times 0.4$ $=9.3 \,kPa$
Pressure at foot level $=p_{\text {heart }}+\rho g h$
$=13.3+10^3 \times 10 \times 1.3$ $=26.3 \,kPa$
So, ratio $=\frac{26.3}{9.3} \approx 2.9$ or $3$
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