A horizontal right angle pipe bend has crosssectional area $=$ $10 $ $cm^2$ and water flows through it at speed $=$ $20$ $m/s$. The force on the pipe bend due to the turning of water is ........ $N$
Medium
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Mass flowing per sec through pipe is $=$ density $\times$ area $\times$ velocity change in velocity $V \times 2^{\frac{1}{2}}$
force$=(\text {density} \times \text {area} \times \text {velocity}) \times\left(\text {velocity} \times 2^{\frac{1}{2}}\right)$
$=565.7 N$
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