MCQ
A horizontal right angle pipe bend has crosssectional area $=$ $10 $ $cm^2$ and water flows through it at speed $=$ $20$ $m/s$. The force on the pipe bend due to the turning of water is ........ $N$
- ✓$565.7$
- B$400$
- C$20$
- D$282.8$
✓
Answer
Correct option: A.
$565.7$
a
Mass flowing per sec through pipe is $=$ density $\times$ area $\times$ velocity change in velocity $V \times 2^{\frac{1}{2}}$
Mass flowing per sec through pipe is $=$ density $\times$ area $\times$ velocity change in velocity $V \times 2^{\frac{1}{2}}$
force$=(\text {density} \times \text {area} \times \text {velocity}) \times\left(\text {velocity} \times 2^{\frac{1}{2}}\right)$
$=565.7 N$
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