A hydrocarbon $\ce{C_5H_{10}}$ does not react with chlorine in dark but gives a single monochloro compound $\ce{C_5H_9Cl}$ in bright sunlight. Identify the hydrocarbon.
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The hydrocarbon can be either a cycloalkane or an alkene since it doesn’t react with $\ce{Cl_2}$ in the dark, it can not be an alkene but must be cycloalkane since the cycloalkane reacts with $\ce{Cl_2}$ in the presence of sunlight to give a single monochloro derivative.
It shows that it is cyclic hydrocarbon in which hall the hydrogen atoms are identical.
Thus, it can be only cyclopentane.
It shows that it is cyclic hydrocarbon in which hall the hydrogen atoms are identical.
Thus, it can be only cyclopentane.
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