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9. Hydricarbon — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry9. Hydricarbon1 Mark
MCQ
A hydrocarbon $X$ adds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. $X$ reacts with $KMn{O_4}$ in presence of acid to give two moles of the same carboxylic acid. The structure of $X$ is
  • A
    $C{H_2} = CH - C{H_2}C{H_2}C{H_3}$
  • B
    $C{H_3}C{H_2}C{H_2} - CH = CHC{H_3}$
  • ✓
    $C{H_3}C{H_2}CH = CHC{H_2}C{H_3}$
  • D
    $C{H_3}CH = CHC{H_2}C{H_2}C{H_3}$
✓

Answer

Correct option: C.
$C{H_3}C{H_2}CH = CHC{H_2}C{H_3}$
c
The reaction of a process:

$CH _3 CH _2 CH = CHCH _2 CH _3+ Br _2 \rightarrow CH _3 CH _2 CHBr - CHBrCH _2 CH _3$

And in presence of acidic $KMnO _4$ alkene is oxidised to form acid.

$CH _3 CH _2 CH = CHCH _2 CH _3+\left( H _2 O + O \right) \longrightarrow 2 CH _3 CH _2 COOH$

So the structure of $X$ is $CH _3 CH _2 CH = CHCH _2 CH _3$

Since it gives two moles of same carboxylic acid on reaction with oxidizing agent potassium permanganate hence it must be symmetrical alkene. Here the only alkene in option $B$ is symmetrical alkene. Thus option $B$ is correct.

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