A large tank is filled with water (density $=$ $10^3 $ $kg/m^3$).A small hole is made at a depth $10$ $m$ below water surface. The range of water issuing out of the hole is Ron ground. What extra pressure must be applied on the water surface so that the range becomes $2R $ (take $1$ $atm$ $=$ $10^5$ $Pa$ and $g$ $=$ $10$ $m/s^2):$ ...... $atm$
Diffcult
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Range will become twice, if the velocity of efflux becomes twice. Since velocity of efflux is
$\sqrt{2 g h},$ it will become twice, if $h$ becomes $4\, times$, or $40 m$
Thus, an extra pressure equivalent to $30 \mathrm{m}$ of water should be applied.
$1atm$ $=0.76 \times 13.6 \mathrm{m}$ of water $=10.336 \mathrm{m}$ of water
$30 m$ of water $\approx 3 a t m$
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