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A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base. If the radius of the vessel is $ r $ and angular velocity of rotation is $\omega $, then the difference in the heights of the liquid at the centre of the vessel and the edge is
  • A$\frac{{r\omega }}{{2g}}$
  • B$\frac{{{r^2}{\omega ^2}}}{{2g}}$
  • C$\sqrt {2gr\omega } $
  • D$\frac{{{\omega ^2}}}{{2g{r^2}}}$
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